coding in java - Printable Version

coding in java - Printable Version

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+---- Thread: coding in java (/thread-2183.html)

Pages: 1 2

coding in java - speX - 2006-02-06

my source code as in my java program code? cause my program is extreamly long.... well its a few hundred lines long lol

coding in java - z0ny - 2006-02-06

That's why I said the *relevant* source code, not the entire one. ;) My guess is that you assign the input directly to an integer variable though it gets read as a string. Maybe your Windows JVM automatically converts the input. But show me the source, Luke. :)

coding in java - speX - 2006-02-07

here it is the menu part

Code:
/Main Menu

	System.out.println ("Please select a option");

	System.out.println ("1. Play Game");

	System.out.println ("2. Instructions");

	System.out.println ("3. High Scores");

	System.out.println ("4. Exit");

	intInput = reader.readInt();

	//Menu Choices

	if (intInput == 1){

		PlayGame();

	}else if (intInput == 2){

		strInstructions();

	}else if (intInput == 3){

		HighScores();

	}else if (intInput == 4){

	}

coding in java - z0ny - 2006-02-07

The data type of your "reader" variable would be interesting, too. I just wrote a small example that *should* work (will test it later, not too much time at the moment):

Code:
import java.io.*;

public class myinput {
	static public void main(String[] args) {
			BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
			int someint = 0;

			System.out.print("Number: ");

			try {
					someint = Integer.parseInt(reader.readLine());
			} catch (IOException e) {
					System.out.println("Input error...");
					System.exit(1);
			}

			System.out.println("Entered "+someint+".");
	}
}